a)
The given quantities are:
is the vertical distance covered by the ball
is the time it takes for the ball to reach the ground
is the initial velocity of the ball
is the acceleration of gravity
is the final velocity of the ball
b)
![25.82 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/b9osje1phezjj7a1ancpnmgqbqz096ej74.png)
In order to find the acceleration of gravity, we use the following equation:
![d=v_0 t + (1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/yyy6h0sd2hs53oil77gbw97taa1w0tyfgv.png)
Where
![v_0 =0](https://img.qammunity.org/2020/formulas/physics/middle-school/syxptx16pmyd7fjes6cmugnr7bblfjhy7h.png)
t = 0.88 s
d = 10.0 m
Solving for a,
![a=(2d)/(t)=(2(10.0))/(0.88^2)=25.82 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/ovtd79z9tp99xdaji6ff6pmell7w87qbhx.png)
c) Jupiter
The value which is closer to the value calculated is the value for Jupiter, which is 25.95, so the planet must be Jupiter.
d) 22.7 m/s
We can find the final velocity of the ball before striking the ground by using the equation
![v_f^2 = v_0^2 +2ad](https://img.qammunity.org/2020/formulas/physics/middle-school/8k1jayg2hali4pncca75em6dp3f1nxj9y5.png)
where
![v_0 =0](https://img.qammunity.org/2020/formulas/physics/middle-school/syxptx16pmyd7fjes6cmugnr7bblfjhy7h.png)
![a=25.82 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/clx5pz3q0113fq3kb3xzvw8wdrhj9pjowf.png)
d = 10.0 m
Solving for v,
![v=√(v_0^2+2ad)=√(0+2(25.82)(10.0))=22.7 m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/6hettbw5yx6ilqw5zpkgwhid3m44zu89w1.png)