Question

The point begin ordered pair, 3, negative 3, end ordered pair is the solution to which of the following systems of equations? A Begin equation . . . 6 times x plus 5 times y equals . . . 3 . . . end equation Begin equation . . . 2 times x plus 4 times y equals . . . negative 6 . . . end equation B Begin equation . . . 2 times x minus 3 times y equals . . . fifteen . . . end equation Begin equation . . . negative x plus 4 times y equals . . . negative 9 . . . end equation C Begin equation . . . 8 times x plus 3 times y equals . . . fifteen . . . end equation Begin equation . . . 5 times x minus 6 times y equals . . . negative thirty three . . . end equation D Begin equation . . . 7 times x minus 2 times y equals . . . twenty seven . . . end equation Begin equation . . . negative 3 times x minus 5 times y equals . . . negative twenty four . . . end equation

Answer 1

so basically for this problem you're just going to plug in the point (3,-3) into every equation, keeping in mind that the 3 is the x value and that the -3 is the y value. once you plug it in you can just use order of operations (pemdas) to solve.

the equations that do work with the point (3,-3) are (2x+4y=-6)

(2x-3y=15)

(8x+3y=15)

(7x-2y=-24)

Explanation:

so to work one of these problems you take (2x+4y=-6) and plug in your variables.

2(3)+4(-3)=-6

then you're going to multiply

6-12=-6

the subtract the negative twelve from the 6

-6=-6

so we get a true statement. if you do this and the two numbers don't match then the equation does not work with your point. I hope this helps!