Answer:
![-2(1)/(2);-(3)/(8);(7)/(8);2(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bgdg5f7y2ruu9tpudp67t5obn48f1q9rm5.png)
Explanation:
Here we need to order all numbers from least to greatest. To do that, we can recur to the decimal number of each fraction.
We have
![-(3)/(8);(7)/(8);-2 (1)/(2) ;2(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fjt62s9sb3t5bkzcah65jvxdmfhait51fm.png)
First, we have to position the negative numbers, because they are less than positive numbers. Between
and -2 \frac{1}{2}, which is the least?
![-(3)/(8) =-0.375](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xm157u1cmudp8bg2mgv1ck530z2fu9589n.png)
![-2(1)/(2) =-2.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d6xq4a698gqd1lzxlel9rezvat635t0owm.png)
Therefore, we have to position
first, second
, because -2.5 is less than -0.375.
To position the other two numbers we do the same process:
![2(1)/(2) =2.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q48uku3jgy7hmqkpialgcfrqjb61hqm5e1.png)
![(7)/(8)=0.875](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uvd3dmjpwwa6auvyp2iz94bqyqn0qovpre.png)
In this case, 2.5 is more than 0.875. So, the fourth number is 0.875 and the fifth number is 2.5.
Therefore, the correct position is:
![-2(1)/(2);-(3)/(8);(7)/(8);2(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bgdg5f7y2ruu9tpudp67t5obn48f1q9rm5.png)