Answer: 28.1 amu
Step-by-step explanation:
Mass of isotope 1 = 27.98 amu
% abundance of isotope 1 = 92.21% =
![(92.21)/(100)=0.9221](https://img.qammunity.org/2020/formulas/chemistry/high-school/sihv4o10tllrszx808kvxlfvooo5e1i5eb.png)
Mass of isotope 2 = 28.98 amu
% abundance of isotope 2 = 4.70% =
![(4.70)/(100)=0.047](https://img.qammunity.org/2020/formulas/chemistry/high-school/wxbeqb4h3cj37fr06vkqebupblo6z3xgn9.png)
Mass of isotope 3 = 29.97 amu
% abundance of isotope 2 = 3.09% =
![(3.09)/(100)=0.0309](https://img.qammunity.org/2020/formulas/chemistry/high-school/bk5cg0u0yess3pn66sykzp3pvjcwtkiabl.png)
Formula used for average atomic mass of an element :
![\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}* {{\text { fractional abundance}})](https://img.qammunity.org/2020/formulas/chemistry/high-school/axjrin9lrs5tj5rhri367s3rfi2dbo7hdb.png)
![A=\sum[(27.98 )* 0.922+(28.98)* 0.047+(29.97)* 0.0309]](https://img.qammunity.org/2020/formulas/chemistry/high-school/1g0b5l7abhn3r91qftbwjon3mngz4ponyx.png)
![A=28.1amu](https://img.qammunity.org/2020/formulas/chemistry/high-school/v2pfa1z3572l9295g6f0e9lin785c99drb.png)
Therefore, the average atomic mass of silicon is 28.1 amu