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How to factor 4x^2-12=2x

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Answer:

2(x - 2)(2x + 3) = 0

Explanation:

Given

4x² - 12 = 2x ( subtract 2x from both sides )

4x² - 2x - 12 = 0 ← factor out 2 from each term

2(2x² - x - 6) = 0

To factor the quadratic

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 6 = - 12 and sum = - 1

The factors are - 4 and + 3

Use these factors to split the x- term

2x² - 4x + 3x - 6 ( factor the first/second and third/fourth terms )

2x(x - 2) + 3(x - 2) ← factor out (x - 2) from each term

(x - 2)(2x + 3), thus

2x² - x - 6 = (x - 2)(2x + 3) and

4x² - 2x - 12 = 0

2(x - 2)(2x + 3) = 0 ← in factored form

User MathiasJ
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