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The larger of two integers is seven more than the smaller integer. Their sum is 49. Find the integers.

User Kidjan
by
7.9k points

1 Answer

2 votes

Answer:

The two integers have values 28 and 21

Explanation:

This is a simultaneous equation problem. Let the two integers be represented by
a and
b.

The first part of the question can be represented by the following equation:


a-b=7

From the second part of the question, we know their sum is 49, which can be represented by:


a+b=49

Now, we need to manipulate the expressions to contain just one unknown value. If we add
b to both sides of the first equation we get:


a=b+7

Now we can substitute the value of
a for
b+7 in the second equation:


a+b=(b+7)+b=49

Which we can then rearrange and solve for
b:


2b +7=49\\2b=42\\b=21

We can now use the value for
b in either of the two original equations for find the value of
a:


a=b+7=(21)+7=28.

We now have the the two values 28 and 21.

Note: To double check the answer, check if their sum is equal to 49:


a+b=28+21=49.

User Nahyshene
by
7.7k points

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