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The equation of the perpendicular line

The equation of the perpendicular line-example-1
User Basilevs
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Answer:

Explanation:

First we need to find the point that the perpendicular line goes through on this line segment. The problem says it's a perpendicular bisector, which means it goes through the middle of the line, which means the point it goes through is halfway between (4, 4) and (-8, 8). This point would be (-2, 6).

Next, we need to find the slope of the perpendicular line. We know that if the slope of the line segment we're given is
m, then the slope of the line perpendicular to this line segment is
(-1)/(m).

The slope of the line segment can be found by the following:


(8 - 4)/(-8 - 4)


(4)/(-12)


(-1)/(3)

This means that the slope of the perpendicular line is 3.

The equation of a line is
y = mx + b, were
m is the slope and
b is the Y-intercept.

We know the slope, we so we just need to determine the Y-intercept. To do so, we can plug in a point that we know the line goes through, (-2, 6), and solve for
b:


6 = (3)(-2) + b


6 = -6 + b


b = 12

Finally, the equation of the line is


y = 3x + 12

User Janneck Lange
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