98.5k views
3 votes
A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 18.1t and y = 4.20t − 4.90t2, where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball's position as a function of time, using the unit vectors î and ĵ. (Give the answer in terms of t.)

1 Answer

2 votes

Answer:

The vector for the ball’s position is
\vec{r} = (18.1t)\hat{i} + (4.20t - 4.90t^2)\hat{j} \:m

Explanation:

The position vector for a particle moving in the x-y plane can be written


\vec{r} = x\hat{i} + y\hat{j}

where x, y, and
\vec{r} change with time as the particle moves while the unit vectors
\hat{i} and
\hat{j} remain constant.

We know that the x and y coordinates as functions of time are given by
x = 18.1t and
y = 4.20t - 4.90t^2, where x and y are in meters and t is in seconds.

Therefore, the vector for the ball’s position is
\vec{r} = (18.1t)\hat{i} + (4.20t - 4.90t^2)\hat{j} \:m

User Untrots
by
8.1k points