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You are moving into an apartment and take the elevator to the 6th floor. Suppose your weight is 790 N and that of your belongings is 960 N. (a) Determine the work done by the elevator in lifting you and your belongings up to the 6th floor (15.2 m) at a constant velocity. (b) How much work does the elevator do on you alone (without belongings) on the downward trip, which is also made at a constant velocity?

User JStead
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1 Answer

6 votes

Answer:

a)
W=26600J

b)
W=-12008J

Step-by-step explanation:

Given the information from the exercise we can calculate the work done by the elevator using the following formula:


W=F*s

a) Considering you and your belongings as a system we know that the elevator is applying a Normal reaction force of:


F=790N+960N=1750N

Since the force applied and the displacement is in the same direction, the work done by the elevator is positive


W=(1750N)(15.2m)=26600J

b) The reaction force applied by the elevator is the same as the weight of the person


F=790N

Since the force applied and the displacement is in opposite direction, the work done by the elevator is negative


W=-(790N)(15.2m)=-12008J

User TimP
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