Question

a gas container is initially at 47 mm Hg and 77 K (liquid nitrogen temperature.) what will the pressure be when the container warms up to room temperature of 25 C?

Answer 1

181.90 mmHg

Step-by-step explanation:

• According to pressure law, the pressure of a gas and its absolute temperature are directly proportional at a constant volume.
• Mathematically,
  `P\alpha T`

• Thus;
  `P=kT`

• Therefore, at varying temperature and pressure;

`(P1)/(T1)=(P2)/(T2)`

In this case, we are given;

Initial temperature, T1 = 77 K

Initial pressure, P1 = 47 mmHg

Final temperature, T2 = 25 °C + 273

= 298 K

We are required to find the final pressure;

Using pressure law;

P2 = (P1/T1)T2

= (47/77K) × 298 K

= 181.90 mmHg

Therefore, the new pressure will be 181.90 mmHg