Answer:
![3^(11)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6591fq566rxlpyl4z1i5vmxippv5jt4d5b.png)
Explanation:
Given you will receive a penny today and the amount is tripled each day
so if we write down each day payment we get a geometric progression.
Day 1=1
Day 2=3
Day 3=9
..
the series is 1,3,9,...
it is a geometric progression with a=1 r=3
we know that the general form of nth term in a GP is t(n)=a
![r^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dcm7m533z6kpkiten8so3pb7808ozhxc15.png)
t(n)=1*
![3^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/k0lb5ylezcwpdoved7c6lei6zo8fd4dg5l.png)
now we need to find the amount on 12th day by substituting n=12
we get
t(12)=
![3^(11)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6591fq566rxlpyl4z1i5vmxippv5jt4d5b.png)
He will pay
on the 12th day .