Question

A crate having mass 50.0 kg falls horizontally off the back of the flatbed truck, which is traveling at 100 km/h. Find the value of the coefficient of kinetic friction between the road and crate if the crate slides 50 m on the road in coming to rest. The initial speed of the crate is the same as the truck, 100 km/h.

Answer 1

`\mu = 0.786`

Step-by-step explanation:

As we know that initial speed of the crate is

`v_i = 100 km/h`

`v_i = 27.78 m/s`

now finally the crate will come to rest

so we have

`v_f = 0`

now the deceleration due to frictional force is given as

`a = -\mu g`

distance moved by the crate before it will stop is given as

`d = 50 m`

so we will have

`0 - 27.78^2 = 2(-\mu(9.81))50`

`\mu = 0.786`