Question

A 4.33 kg cat has 41.7 J of KE. how fast is the cat moving?(unit=m/s)

Answer 1

The answer to your question is: v = 4.39 m/s

Step-by-step explanation:

Data

mass = 4.33 Kg

KE = 41.7 J

v = ?

Formula

`KE = (1)/(2) mv^(2)`

`v = \sqrt{(2KE)/(m) }`

`v = \sqrt{(2(41.7))/(4.33) }`

`v = √(19.26)`

v = 4.39 m/s