Question

A 0.150 kg baseball has 118 j of KE. how fast is the ball moving?(unit=m/s)

Answer 1

Answer: 39.67

Explanation: 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s

since KE = m/2*V^2 ,

then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).

Answer 2

v = 5.95 m/s

Step-by-step explanation:

Given,

The mass of the baseball, m = 0.150 Kg

The kinetic energy (K.E) of the baseball, E = 118 J

The kinetic energy of a body is directly proportional to the square of its velocity. The formula for kinetic energy is given by

E = 1/2 mv² joules

Solving for v

v² = 2mE

`v = √(2mE)` m/s

Substituting the given values in the above equation,

`v = √(2X0.15X118)`

v = 5.95 m/s

Hence, the velocity of the baseball is, v = 5.95 m/s