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Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°

Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°-example-1

1 Answer

4 votes

Answer:

The answer to your question is: the first option - 9/
√(80)

Explanation:

Process

cosФ = adjacent side / hypotenuse

-1/9 = adjacent side / hypotenuse

adjacent side = -1 hypotenuse = 9

c² = a² + b²

b² = c² - a²

b² = 81 - 1

b =
√(80) \\ b = opposite side

But b is negative because we are in the third quadrant.

b = -
√(80)

Finally csc Ф = hypotenuse / opposite side

csc Ф = - 9 /
√(80)

User Adnan Ahmed
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