Question

A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength? A. 0.034 newtons/amp·meter B. 0.17 newtons/amp·meter C. 0.26 newtons/amp·meter D. 0.77 newtons/amp·meter E. 6.0 newtons/amp·mete

Answer 1

B= magnetic field strength

Step-by-step explanation:

use formula E = Blv

l=length

v=speed

this works if field &wire carrying current is perpendicular only

make sure you get your units right

Answer 2

Magnetic field strength,
`B=6\ N/A-m`

Step-by-step explanation:

Given that,

Length of the wire, l = 0.36 m

Speed with which the wire moves in a magnetic field, v = 0.21 m/s

The induced emf produced in the wire is 0.45 volts,
`\epsilon=0.45\ V`

It is a case of motional emf. When a wire moves in a magnetic field with velocity v, an emf is induced in the wire. It is given by :

`\epsilon=Blv`

B is the magnetic field strength

`B=(\epsilon)/(lv)`

`B=(0.45\ V)/(0.36\ m* 0.21\ m/s)`

`B=5.95\ N/A-m`

or

`B=6\ N/A-m`

So, the magnetic field strength is 6 N/A. Hence, this is the required solution.