Answer:

Explanation:
First, to obtain the gradient we must rearrange the equation into the form
, where
is the gradient and
is the y-intercept (the point where the line crosses the y-axis).
To rearrange to this form, take away
from both sides and divide by 5:

From this equation, we can see the gradient is
and the y-intercept is

Now, to obtain the equation of the line parallel to
we must find the new y-intercept. To do this, rearrange
to find
.

We know the value of
from above (
), and the coordinates the line must pass through are in the question (2, -1).
We just put those values into the equation and solve for
:

Now, rearrange back to the original form and you obtain the answer:
