The percentage of the entire population in lactose intolerant is 25.7% The percentage of people who are lactose intolerant is 14%
Based on the data that follows
The subject of Event W is White Americans.
The subject of Event B is Black Americans.
The topic of Event A is Asian Americans in the US.
The topic of Event L is lactose intolerance.
Afterwards, the probabilities that are
P(W) = 0.82
P(B) = 0.14
P(A) = 0.04
Now Conditional probability of Lactose intolerant for White, Black, and Asian people is
P(L/W) = 0.15
P(LIB) = 0.70
P(LA) = 0.90
1)
By summing up the probabilities of lactose intolerance in each racial group and weighting them according to their respective population proportions, we can use the conditional probability approach to determine the chance of lactose intolerance in the overall population.
The probability of the entire population in lactose intolerant is given by
P(L) = P(W)P(LW) + P(B)P(LB) + P(A)P(LA)
= 0.82 × 0.15 +0.14 x 0.70 +0.04 x 0.90 0.257
The percentage of the entire population in lactose intolerant is 25.7%
2)
By multiplying the conditional likelihood of being Asian given lactose intolerance by the prior probability of being Asian and dividing the result by the prior probability of lactose intolerance, we can use the Bayes theorem to get the probability of being Asian given lactose intolerance.
The probability of people who are lactose intolerant are Asian is
P(A|L) =

P(A|L) =

P(A|L) = 0.140077
The percentage of people who are lactose intolerant are Asian is 14%