Question

a boy sliding down a hill accelerates at 1.4 m/s^2. if he ran and started at 3.0 m/s, how fast will he be going after 5.0s?

Answer 1

10.0 m/s

Step-by-step explanation:

The boy is moving with uniform accelerated motion, so we can use the following suvat equation:

v = u + at

where

v is the velocity at time t

u is the initial velocity

a is the acceleration

For the boy in the problem,

u = 3.0 m/s

`a=1.4 m/s^2`

Substituting t = 5.0 s, we find the velocity of the boy at that time:

`v=3.0 + (1.4)(5.0)=10.0 m/s`