Answer:
![-1.13 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/fjaiyi8ntgdc9nwubpbyqsmnjhslqqhosu.png)
Step-by-step explanation:
The acceleration of an object is given by:
![a=(v-u)/(t)](https://img.qammunity.org/2020/formulas/physics/middle-school/rbz9i28f98a6dvpx0ghax9pxq7qjfdf5sd.png)
where
v is the final velocity
u is the initial velocity
t is the time it takes for the velocity to change from u to v
For this problem, first we have to convert the velocities of the car from mph to m/s:
![u = 65 mi/h \cdot (1609 m/mi)/(3600 s/h)=29.1 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/6xyuo30hlrblqb7fudar3im1bes4yb9zjp.png)
![v = 55 mi/h \cdot (1609 m/mi)/(3600 s/h)=24.6 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/iz08l1q1q4zwx5vshoi4ybq3ofry91kf2p.png)
While the time interval is
t = 4.0 s
Substituting, we find the acceleration:
![a=(24.6-29.1)/(4.0)=-1.13 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/6yqwsywqfnojfdmw1fta717znhyyn81ods.png)