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5 votes
Б) 3х2 – 10 = 152
how to solve with square root​

User Sody
by
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1 Answer

4 votes

Answer:


3√(6) and
-3√(6)

Explanation:

We will take numbers to one side and variables to one side eliminate the "Square" with "Square Root" and solve for the variable x. The process is shown below:


3x^2-10=152\\3x^2=152+10\\3x^2=162\\x^2=(162)/(3)\\x^2=54\\x=√(54)

Now, we need to reduce the radical by using the rule shown below:


√(x*y)=√(x)  √(y)

Now,


√(54)=√(6*9) =√(6)  √(9) =3√(6)

The correct answer is
3√(6) and
-3√(6)

Note: squaring positive and negative makes the same answer

User Volna
by
8.6k points

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