Question

Four consecutive positive prime numbers have a sum that is divisible by three. What is the smallest possible value of this sum?

Answer 1

36

Explanation:

1 + 3 + 5 + 7 = 16

3 + 5 + 7 + 11= 26

These consecutive positive prime numbers above have sums that are not divisible by three.

5 + 7 + 11 + 13 = 36

This consecutive positive prime numbers above has a sum that is divisible by three: 36.

36 : 3 = 12