Question

Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 32.4 g of carbon and 373 g of chlorine, and the other sample produced 12.3 g of carbon and 112 g of chlorine.Are these results consistent with the law of constant composition?Yes or NoHow many hydrogen atoms are in each of the following chemical formulas?1) H3PO42) Na2HPO43) Ca(HCO3)24) Ba(C2H3O2)2

Answer 1

The answer to your question is:

Step-by-step explanation:

Law of constant composition states that a given compound always contains its component elements in a fixed ratio.

Data

Sample 1 32.4 g of C and 373 g of Cl

Sample 2 12.3 g of C and 112 g of Cl

Convert the grams to moles and compare the ratios

Sample 1 Sample 2

12 g of C --------------- 1 mol 12 g of C -------------- 1 mol

32.4 g ---------------- x 12.3 ------------- x

x = (32.4 x 1) / 12 x = (12.3 x 1) / 12

x = 2.7 moles of C x = 1.025 moles of C

35.5 g of Cl ---------- 1 mol 35.5 g of Cl ---------- 1 mol

373 g ------------------ x 112 g of Cl ----------- x

x = (373 x 1) / 35.5 x = (112 x 1) / 35.5

x = 10.5 moles of Cl x = 3.15 moles of Cl

Ratio

10.5 / 2.7 = 3.9 3.15/1.025 = 3.1

The ratio must be equal in both samples to say that the law is constant. So the answer is NO.

2.-

1) H3PO4 3 hydrogens

2) Na2HPO4 1 hydrogen

3) Ca(HCO3)2 2 hydrogens

4) Ba(C2H3O2)2 6 hydrogens