Question

A man walks forward on a bus. To a stationary observer, the bus moves east

at a speed of 18 m/s. If the man moves 1.5 m/s east relative to the bus, what
is his velocity in the frame of reference of a stationary observer?

Answer 1

Answer:19.5 m/s east

Step-by-step explanation:

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Answer 2

+19.5 m/s

Step-by-step explanation:

In the reference frame of the stationary observer, the bus is moving east at 18 m/s, so its velocity is:

v = +18 m/s

Where we have taken east as positive direction.

In the reference frame of the bus, the man is moving 1.5 m/s also east, so its velocity is

`v_m' = +1.5 m/s`

Therefore, the velocity of the man in the reference frame of the stationary observer will be:

`v_m = v + v_m' = +18 + 1.5 = +19.5 m/s`