Answer:
The formula for the nth term of the sequence is:
![a_n=a_1\cdot r^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ul4ahude4jolk1usgr0rc6tp26o0pk0xmj.png)
Explanation:
Given the sequence
6, -6, 6, -6
A geometric sequence has a constant ratio r and is defined by
![a_n=a_1\cdot r^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ul4ahude4jolk1usgr0rc6tp26o0pk0xmj.png)
Computing the ratios of all the terms of the adjacent terms
![(-6)/(6)=-1,\:\quad (6)/(-6)=-1,\:\quad (-6)/(6)=-1](https://img.qammunity.org/2022/formulas/mathematics/high-school/cakr1zly9q5c8bfkaqe7na8apguncsd77i.png)
The ratio of all the adjacent terms is the same and equal
so
r = -1
so substituting r = -1 and
in the geometric sequence
![a_n=a_1\cdot r^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ul4ahude4jolk1usgr0rc6tp26o0pk0xmj.png)
![a_n=6\left(-1\right)^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/4nxau7a9g2ko81ytizo7q5nvrzr1hsksnp.png)
Thus, the formula for the nth term of the sequence is:
![a_n=a_1\cdot r^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ul4ahude4jolk1usgr0rc6tp26o0pk0xmj.png)