2 Answers

Prakash Karena · Answer 1 · 2020-12-10T07:52:45+0000

Explanation:

The first step is to setup the division problem

$3x - 1 \sqrt{9 {x}^(2) } - 6x + 2$

Next we divide

$9 {x}^(2) / 3x = 3x$

So now we have to multiply 3x by 3x and -1 by 3x

$3x * 3x = 9 {x}^(2) \\ - 1 * 3x = - 3x$

Then

$\: \: \: \: 9 {x}^(2) - 9 {x}^(2) = 0$

- 6x + 3x = - 3x

Now we divide

- 3x / 3x = - 1

Now multiply

- 1 * - 1 = 1

Now we

$- 3x + 3x = 0 \\ 2 - 1 = 1$

So the answer is

3x-1 Remains 1/3x-1

$3x - 1 + \: \frac {1}{3x - 1}$

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