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5 votes
Find three consecutive intergers such that the sum of twice the smallest and 3 times the largest is 126

User MohitC
by
4.6k points

1 Answer

2 votes

Answer:Answer:

24

,

25

,

26

Explanation:

Let's call the smallest integer

n

. Then the next two consecutive integers are

n

+

1

and

n

+

2

.

"Sum of twice the smallest and 3 times the largest is 126"

2

(

n

)

+

3

(

n

+

2

)

=

126

2

n

+

3

n

+

6

=

126

5

n

+

6

=

126

5

n

=

120

n

=

24

So the smallest integer is

24

.

The three consecutive integers are then:

24

,

25

, and

26

.

User Teysz
by
5.1k points