Answer:
Well I got 9 log 10 (2)/ 3-3log10 (5)
Please correct me if I am wrong
Explanation:
You have to apply the rule alogc (b) (b^a)
=
![\frac{log10(\sqrt{8))^(4)-log10(((1)/(2)))^(3)) } }{3-6log10(√(5)) }](https://img.qammunity.org/2022/formulas/mathematics/high-school/4ktt08jg1ok0lp4z7h321zw7ft3hqshmnq.png)
\frac{\log _{10}\left(\frac{\left(\sqrt{8}\right)^4}{\left(\frac{1}{2}\right)^3}\right)}{3-6\log _{10}\left(\sqrt{5}\right)}