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In a bag are blue green and red marbles. 50% are blue and thirty percent are green. There are 6 red marbles in the bag. If you increase the number of blue marbles by 40%, how many blue marbles will be in the bag

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Answer:

There will be 21 blue marbles

Explanation:

In a bag are blue, green and red marbles. Let x be the number of all marbles in the bag.

50% of all marbles are blue. 50% is exactly half of the marbles, so there are
(x)/(2) blue marbles.

30% of all marbles are green, so there are
x\cdot 0.3=0.3x green marbles.

The rest marbles are red marbles, so there are
x-(1)/(2)x-0.3x=x-0.5x-0.3x=0.2x red marbles.

There are 6 red marbles in the bag, thus


0.2x=6\\ \\2x=60\\ \\x=30

Hence, there are


  • 30\cdot (1)/(2)=15 blue marbles;

  • 30\cdot 0.3=9 green marbles;
  • 6 red marbles.

If you increase the number of blue marbles by 40%, then

15 - 100%

x - 140% (increased by 40%)

Write a proportion:


(15)/(x)=(100)/(40)

Cross multiply:


100x=15\cdot 140\\ \\100x=2,100\\ \\x=21

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