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Hello MathPhys hehe im back

Hello MathPhys hehe im back-example-1
User Ozkary
by
7.7k points

1 Answer

1 vote

Answer:

121 N

Step-by-step explanation:

The component of the weight parallel to the inclined plane is:

mg sin θ

Given mg = 200.2 N and θ = 37.1°:

200.2 sin 37.1°

121

User Ptman
by
6.8k points