Question

From stations A and B, the distance between which is 910 mi,

two trains left simultaneously moving towards each other. The
speed of one train was 10 mph greater than the speed of the
other one. In 5 hours the trains met. Find the speed of each train.

Answer 1

The slowest train goes at 86 mph and the fastest train goes at 96 mph.

Explanation:

Distance and Speed

Assume x is the speed of the slowest train, therefore the speed of the fastest train is x+10.

The distance is calculated as:

d = vt

Where v is the speed and t is the time.

The distance traveled by each train in 5 hours is:

Slowest: 5x

Fastest: 5(x+10)

The sum of both distances is 910 miles:

5x + 5(x + 10) = 910

Operating:

5x + 5x + 50 = 910

10x = 910 - 50 = 860

x = 860/10

x = 86

The slowest train goes at 86 mph and the fastest train goes at 96 mph.