Question

The length of the famed fred's fence is 5 more than twice it's width if the perimeter of the fence is 510 feet find the dimensions of his fenced in area

Answer 1

• 83 1/3 ft wide
• 171 2/3 ft long

Explanation:

Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:

P = 2(L+W)

510 = 2(2w+5 +w) . . substitute given values

255 = 3w +5 . . . . . . divide by 2

250 = 3w . . . . . . . . . subtract 5

83 1/3 = w . . . . . . . . .divide by 3; the width of the area

2w+5 = 171 2/3 . . . . the length of the area

The fenced area is 83 1/3 ft wide and 171 2/3 ft long.