Question

I need help with the b!!!!!
Please

Answer 1

`(3)/(y^(22))`

Explanation:

To simplify the expression we need to understand one rule of exponents.

That is:

`(ab)^x=a^xb^x`

Using this property, we can write:

`(3y^5)^(-2)*(2y^(-4))^(3)\\=(3)^(-2)(y^5)^(-2)*(3)^3 (y^(-4))^3\\`

Now, we use 2 other properties to simplify this further:

1.
`a^(-x)=(1)/(a^x)`

2.
`(a^b)^c=a^(b*c)`

So, now we simplify further:

`(3)^(-2)(y^5)^(-2)*(3)^3 (y^(-4))^3\\=(1)/(3^2)y^(-10)*(27)y^(-12)\\=(1)/(9)y^(-10)(27)y^(-12)\\=((1)/(9)*27)y^(-10)y^(-12)\\=3y^(-10-12)\\=3y^(-22)`

Or in positive exponents, that is:

`3y^(-22)\\=(3)/(y^(22))`