Answer:
The population isn't in the Hardy-Weinberg equilibrium because researchers are studying a small milkweed populatión and one of the conditions of the Hardy-Weinberg equilibrium is that it happens in large populations. The frequencies for the T allele is 0.7 and for the t allele is 0.3
Step-by-step explanation:
To calculate the frequencies of T and t alleles in the population we need to take into account that the following probabilities for each allele to be expressed:
TT => p(T) = 1.0 p(t) = 0.0
Tt => p(T) = 0.5 p(t) = 0.5
tt => p(T) = 0.0 p(t) = 1.0
To calculate the frequencies for each allele we need to use the following expressions
For T:
f(T) = 1.0 (TT) + 0.5 (Tt)
f(T) = 1.0 (0.56) + 0.5 (0.28)
f(T) = 0.56 + 0.14
f(T) = 0.7
For t:
f(t) = 1.0(tt) + 0.5 (Tt)
f(t) = 1.0(0.16) + 0.5 (0.28)
f(t) = 0.16 + 0.14
f(t) = 0.3
The actual allele frequencies in the population are f(T) = 0.7 and f(t) = 0.3.
Now the Hardy - Weinberg equilibrium states that a population will remain the same if it isn't modified by external factors. For this to happen it must fulfill the following conditions:
- There must be no selection
- No mutation
- It should be a large population.
- No random mating
- No migration.
As the researchers are studying a small milkweed population it doesn't fulfills the conditions of a large population and in consequence we can't say this population is in the Hardy - Weinberg equilibrium.