Answer:
Number of moles of Zn = 2.88 mol
Number of moles CH₄ = 1.08 mol
0.232 mole of C₆H₁₂O₆
Step-by-step explanation:
Given data:
Mass of Zn = 188.0 g
Number of moles of Zn = ?
Solution:
Number of moles = mass / molar mass
Number of moles = 188.0 g / 65.38 g/mol
Number of moles = 2.88 mol
24.2 L of CH₄ at STP.
PV = nRT
n = PV/RT
n = 1 atm . 24.2 L / 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 K.
n = 1 atm . 24.2 L / 22.43 atm. L. mol⁻¹
n = 1.08 mol
1.4 ×10³ molecules of C₆H₁₂O₆
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 1.4 ×10²³ molecules of C₆H₁₂O₆
1 mole = 6.022 × 10²³ molecules
(1 mole/6.022 × 10²³ molecules) × 1.4 ×10²³ molecules
0.232 mole of C₆H₁₂O₆