Question

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 3.7× 104 kg, and the force causes its speed to change from 7500 to 4500m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.7× 106 m determine the magnitude of the force.

Answer 1

666000000000 J

391764.71 N

Step-by-step explanation:

u = Initial velocity

v = Final velocity

s = Displacement

Change in energy

`\Delta KE=(1)/(2)m(v^2-u^2)\\\Rightarrow \Delta KE=(1)/(2)3.7* 10^4(4500^2-7500^2)\\\Rightarrow \Delta KE=-666000000000\ J`

Work done be the force is 666000000000 J

`W=F* s\\\Rightarrow F=(W)/(s)\\\Rightarrow F=(-666000000000)/(1.7* 10^6)\\\Rightarrow F=-391764.71\ N`

The magnitude of force is 391764.71 N