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determine the standard form of the equation of the line that passes through (6,0) and (2,-7). (-7x-4y=-42) (7x-4y=42) (-7x+4y=42) (4x+7y=-42)​

1 Answer

7 votes

Answer:


7x - 4y = 42

Explanation:

Given


(x_1,y_1) = (6,0)


(x_2,y_2) = (2,-7)

Required

Determine the equation in standard form

First, calculate the slope (m) using:


m = (y_2 -y_1)/(x_2 - x_1)

This gives:


m = (-7 -0)/(2 - 6)


m = (-7)/(-4)


m = (7)/(4)

The equation in standard form is calculated using:


y - y_1 = m(x - x_1 )

This gives:


y - 0 = (7)/(4)(x - 6)


y = (7)/(4)(x - 6)

Cross Multiply


4y = 7(x - 6)

Open bracket


4y = 7x - 42

Subtract 7x from both sides


-7x + 4y = 7x - 7x - 42


-7x + 4y = - 42

Multiply through by -1


-1(-7x + 4y) = - 42*-1


7x - 4y = 42

User Jan Aagaard
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