Question

M2-5m-14=0
quadratic formula​

Answer 1

-2

Explanation:

Answer 2

`\bf m^2-5m-14=0 ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}m^2\stackrel{\stackrel{b}{\downarrow }}{-5}m\stackrel{\stackrel{c}{\downarrow }}{-14}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ m= \cfrac{ - (-5) \pm \sqrt { (-5)^2 -4(1)(-14)}}{2(1)}\implies m=\cfrac{5\pm√(25+56)}{2} \\\\\\ m=\cfrac{5\pm√(81)}{2}\implies m=\cfrac{5\pm 9}{2}\implies m= \begin{cases} 7\\ -2 \end{cases}`