187k views
0 votes
3The frequency (in Hz) of a vibrating violin string is given by f = 1 2L s T rho where L is the length of the string (in meters), T is the tension of the string (in Newtons), and rho is the linear density of the string. a) Find the derivative of f with respect to: i. L (assuming T and rho are constants) ii. T (assuming L and rho are constants) iii. rho (assuming L and T are constants)

1 Answer

3 votes

Answer:

(i)
(df)/(dL)=-(1)/(2L^2)\sqrt{(T)/(\rho)}

(ii)
(df)/(dT)=(1)/(4L√(T\rho))

(iii)
(df)/(d\rho)=-\frac{√(T)}{4L\rho^{-(3)/(2)}}}

Explanation:

Let as consider the frequency (in Hz) of a vibrating violin string is given by


f=(1)/(2L)\sqrt{(T)/(\rho)}

(i)

Differentiate f with respect L (assuming T and rho are constants).


(df)/(dL)=(d)/(dL)(1)/(2L)\sqrt{(T)/(\rho)}

Taking out constant terms.


(df)/(dL)=(1)/(2)\sqrt{(T)/(\rho)}(d)/(dL)(1)/(L)


(df)/(dL)=(1)/(2)\sqrt{(T)/(\rho)}(-(1)/(L^2))


(df)/(dL)=-(1)/(2L^2)\sqrt{(T)/(\rho)}

(ii)

Differentiate f with respect T (assuming L and rho are constants).


(df)/(dT)=(d)/(dT)(1)/(2L)\sqrt{(T)/(\rho)}

Taking out constant terms.


(df)/(dT)=(1)/(2L)\sqrt{(1)/(\rho)}(d)/(dT)√(T)}


(df)/(dT)=(1)/(2L)\sqrt{(1)/(\rho)}((1)/(2√(T)))


(df)/(dT)=(1)/(4L√(T\rho))

(iii)

Differentiate f with respect rho (assuming L and T are constants).


(df)/(d\rho)=(d)/(d\rho)(1)/(2L)\sqrt{(T)/(\rho)}

Taking out constant terms.


(df)/(d\rho)=(√(T))/(2L)(d)/(d\rho)(\rho)^{-(1)/(2)}}


(df)/(d\rho)=(√(T))/(2L)(-(1)/(2)(\rho)^{-(3)/(2)}})


(df)/(d\rho)=-\frac{√(T)}{4L\rho^{-(3)/(2)}}}

User RobWhistler
by
8.9k points