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If point (1 - p,y) belongs to the graph of the function which point must along also belong to the graph

2 Answers

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Final answer:

If the point (1 - p, y) belongs to the graph of the function, any point(s) with the x-coordinate of 1 - p will also belong to the graph. The y-coordinate can vary for these points.

Step-by-step explanation:

f the point (1 - p, y) belongs to the graph of a function, we can determine which other point(s) must also belong to the graph by analyzing the given information.

Let's break it down:

  • 1. The x-coordinate of the given point is 1 - p.
  • 2. The y-coordinate of the given point is y.

To find the corresponding point(s) that must also belong to the graph, we need to consider the behavior of the function.

Since the x-coordinate of the given point is 1 - p, any other point that also belongs to the graph must have the same x-coordinate. Therefore, we can conclude that the point(s) (1 - p, _) must also belong to the graph, where "_" represents any possible y-coordinate.

In other words, all points that have an x-coordinate of 1 - p will be part of the graph.

To summarize, if the point (1 - p, y) belongs to the graph of the function, any point(s) with the x-coordinate of 1 - p will also belong to the graph. The y-coordinate can vary for these points.

User Shashank Shah
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6 votes

Answer:

We have seen that some equations in x and y do not describe y as a function of x. The algebraic way see if an equation determines y as a function of x is to solve for y. If there is not a unique solution, then y is not a function of x.

Suppose that we are given the graph of the equation. There is an easy way to see if this equation describes y as a function of x.

Step-by-step explanation:

User ThinkFloyd
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