Question

A current of 250 amps is flowing through a copper wire with a resistance of

2.09 x 10^-4 ohms. What is the voltage?​

Answer 1

V= 5.225*10^-2 volts

Step-by-step explanation:

from ohms law

V=IR

where R= 2.09*10^-4

I=250A

V=2.09*10^-4*250

V= 5.225*10^-2 volts