Answer:
You should expect 1.08 vehicles to be hybrid.
Explanation:
For each vehicle, there are only two possible outcomes. Either it is a hybrid, or it is not. The probability of a vehicle being a hybrid is independent of other vehicles. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
![E(X) = np](https://img.qammunity.org/2020/formulas/mathematics/college/3bk54jyet3zf9d1ttkfgkk3hm6rop2x236.png)
2.7 percent of the new car sales are hybrids in the first quarter of 2016.
This means that
![p = 0.027](https://img.qammunity.org/2020/formulas/mathematics/college/ucsko2kifddjit9k49s5kkrlixvvuwrr1w.png)
For a sample of 40 vehicles sold in the Richmond, Virginia
This means that
![n = 40](https://img.qammunity.org/2020/formulas/mathematics/college/z0a5iil5bmi1ju2b3kpankxjqiiuhbz0or.png)
For a sample of 40 vehicles sold in the Richmond, Virginia
![E(X) = np = 40*0.027 = 1.08](https://img.qammunity.org/2020/formulas/mathematics/college/zrof5eahmhomy2vpg3xg28vp78ulc5qqg5.png)
You should expect 1.08 vehicles to be hybrid.