Answer: Hello there!
we have the function f(x) = IxI/x
let's analyze it:
when x is a positive number, suppose x = a, where a is positive, we have:
f(a) = IaI/a = a/a = 1
and this is independent of the number a, so for all the positive values of x, we have f(x) = 1
Now if x is negative, suppose x = -a, we have:
f(-a) = I-aI/(-a) = a/(-a) = -1
and again, this does not depend on the value of a, so for all the negative values of x, we have f(x) = -1.
And in x = 0 we have a little discontinuity, where f(0) is indefined.
Then this function can be piecewise writen as:
f(x) = 1 if x > 0
f(x) = -1 if x < 0