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An aquifer has three different formations. Formation A has a thickness of 22 ft and a hydraulic conductivity of 17.0 ft/d. Formation B has a thickness of 3.5 ft and hydraulic conductivity of 99 ft/d. Formation C has a thickness of 26 ft and hydraulic conductivity of 22 ft/d. Assume that each formation is isotropic and homogeneous. Compute both the overall horizontal and vertical conductivities.

User Negabaro
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1 Answer

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Answer:


k_h=25.09\ ft/d


k_v=20.5ft/d

Step-by-step explanation:

Given that

h₁= 22 ft ,k₁= 17 ft/d

h₂= 3.5 ft, k₂=99 ft/d

h₃=26 ft ,k₃=22 ft/d

Horizontal conductivity


k_h=(k_1h_1+k_2h_2+k_3h_3)/(h_1+h_2+h_3)

Now by putting the values


k_h=(17* 22+3.5* 99+26* 22)/(22+3.5+26)\ ft/d


k_h=25.09\ ft/d

Vertical conductivity


k_v=(h_1+h_2+h_3)/((h_1)/(k_1)+(h_2)/(k_2)+(h_3)/(k_3))


k_v=(22+3.5+26)/((22)/(17)+(3.5)/(99)+(26)/(22))\ ft/d


k_v=20.5ft/d

User Isabela
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