Question

Two factory plants are making TV panels. Yesterday, Plant A produced 4000 panels. One percent of the panels from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 3%?

Answer 1

Answer: 8000

Explanation:

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0.1x + 0.03y = 0.06(x + y)

0.1*6000 + 0.03y = 0.06(6000 + y)

600 + 0.03y = 0.06*6000 + 0.06y

0.06y - 0.03y = 600 - 360

0.03y = 600 - 360

y = (600 - 360)/0.03

y = 8000

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answer:

y = panels produced by plant B = 8000