Answer: a)
, b)
c) $5761.36.
Explanation:
Since we have given that
Unit price is expressed as
![p=480.03x^2+1](https://img.qammunity.org/2020/formulas/mathematics/college/d3c42effcghoom8v6vo33s6za6o0juggbt.png)
Let x be the number of units of a thousands.
So, Revenue function is given by
![R(x)=px\\\\R(x)=x(480.03x^2+1)\\\\R(x)=480.03x^3+x](https://img.qammunity.org/2020/formulas/mathematics/college/ixgt03bnoavk62ask1v0f6go9vsz58hq0d.png)
.(b) Find the marginal revenue function R'..
Marginal revenue function becomes,
![R'(x)=3* 480.03x^2+1\\\\R'(x)=1440.09x^2+1](https://img.qammunity.org/2020/formulas/mathematics/college/oi2l2izpy5sg69tkvqgfjyhhbbnk8xnein.png)
(c) Compute R'(2).
![R'(2)=1440.09(2)^2+1\\\\R'(2)=5760.36+1\\\\R'(2)=5761.36](https://img.qammunity.org/2020/formulas/mathematics/college/6lu37nu9ddi3w4qxy20ozqidbvs6tgk5i3.png)
Hence, a)
, b)
c) $5761.36.