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What is the tangential acceleration of a bug on the rim of a 7.0 inch diameter disk if the disk moves from rest to an angular speed of 80 rev/min in 5.0 seconds?

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Answer:

5.9 in/s²

Step-by-step explanation:

Tangential acceleration is the change in linear velocity over time.

a = Δv / t

Linear velocity is angular velocity times radius.

v = ωr

Therefore:

a = rΔω / t

a = (3.5 in) (80 rev/min × 2π rad/rev × 1 min/60 s) / (5.0 s)

a = 5.9 in/s²

User Damjan Pavlica
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