Question

A penny is dropped from the top of a 320 m high building how fast is it moving when it hits the ground

Answer 1

79.2363553 meters per second

Step-by-step explanation:

Let's use an equation of constant acceleration:

`v^2=v_0^2-2g(x-x_0)\\`

Where g is the acceleration caused by gravity.

We have
`x-x_0=-320 [tex]v^2=(0(m)/(s))^2-2(9.81(m)/(s^2))(-320m)\\\\v^2=0-(19.62(m)/(s^2))(-320 m)\\\\v^2=6278.4 (m^2)/(s^2)\\\\v=\sqrt{6278.4 (m^2)/(s^2)}\\\\v=79.2363553(m)/(s)  (approx.)`m[/tex] and know that
`v_0=0(m)/(s)`