Question

A pool is 59.9 m long and 34.6 m wide. If the average depth of water is 3.00 ft, what is the ma

of water in the pool? Enter your answer in scientific notation.
The density of water is 1.0 g/mL.
19.144
x 10 1
kg

Answer 1

Mass = 6.218×
`10^(6)` kg

Explanation:

calculate the volume of the pool:

`v=(59.9)(34.6)(3.00)=6217.62m^(3)`

calculate the number of litres:

`v=6217.62(1000)=6217620liters`

calculate the mass

1g----1ml

1000g----1000ml

1kg = 1 liter of water

Mass = 6.218×
`10^(6)` kg

Hope this helps