Question

1f 3.8 kcal is released by combustion of each gram of

glucose, how many kilocalories are released by the
combustion of 1.50 mol of glucose?​

Answer 1

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose

Step-by-step explanation:

First we have to calculate the amount in grams in 1.5 moles of glucose by using formula

Molecular mass of glucose is 180.156 g/mol

Mass in grams = Molarity x Molecular mass

=1.50 moles x 180.156 g/mol

= 270.23 g

Now we will calculate the amount of energy released

Energy released by 1 gram of glucose = 3.8 Kcal

Energy released by 270.23 gram of glucose = 3.8 x 270.23 Kcal

= 1026.88 Kcal

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose